Integrand size = 18, antiderivative size = 336 \[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\frac {184 a^2 p^2 x}{75 b^2}-\frac {64 a p^2 x^3}{225 b}+\frac {8 p^2 x^5}{125}-\frac {184 a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{75 b^{5/2}}+\frac {4 i a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2}{5 b^{5/2}}+\frac {8 a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )+\frac {4 i a^{5/2} p^2 \operatorname {PolyLog}\left (2,1-\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}} \]
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Time = 0.26 (sec) , antiderivative size = 336, normalized size of antiderivative = 1.00, number of steps used = 20, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.722, Rules used = {2507, 2526, 2498, 327, 211, 2505, 308, 2520, 12, 5040, 4964, 2449, 2352} \[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\frac {4 a^{5/2} p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {4 i a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2}{5 b^{5/2}}-\frac {184 a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{75 b^{5/2}}+\frac {8 a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}}+\frac {4 i a^{5/2} p^2 \operatorname {PolyLog}\left (2,1-\frac {2 \sqrt {a}}{i \sqrt {b} x+\sqrt {a}}\right )}{5 b^{5/2}}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {184 a^2 p^2 x}{75 b^2}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {64 a p^2 x^3}{225 b}+\frac {8 p^2 x^5}{125} \]
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Rule 12
Rule 211
Rule 308
Rule 327
Rule 2352
Rule 2449
Rule 2498
Rule 2505
Rule 2507
Rule 2520
Rule 2526
Rule 4964
Rule 5040
Rubi steps \begin{align*} \text {integral}& = \frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {1}{5} (4 b p) \int \frac {x^6 \log \left (c \left (a+b x^2\right )^p\right )}{a+b x^2} \, dx \\ & = \frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {1}{5} (4 b p) \int \left (\frac {a^2 \log \left (c \left (a+b x^2\right )^p\right )}{b^3}-\frac {a x^2 \log \left (c \left (a+b x^2\right )^p\right )}{b^2}+\frac {x^4 \log \left (c \left (a+b x^2\right )^p\right )}{b}-\frac {a^3 \log \left (c \left (a+b x^2\right )^p\right )}{b^3 \left (a+b x^2\right )}\right ) \, dx \\ & = \frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {1}{5} (4 p) \int x^4 \log \left (c \left (a+b x^2\right )^p\right ) \, dx-\frac {\left (4 a^2 p\right ) \int \log \left (c \left (a+b x^2\right )^p\right ) \, dx}{5 b^2}+\frac {\left (4 a^3 p\right ) \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{a+b x^2} \, dx}{5 b^2}+\frac {(4 a p) \int x^2 \log \left (c \left (a+b x^2\right )^p\right ) \, dx}{5 b} \\ & = -\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {1}{15} \left (8 a p^2\right ) \int \frac {x^4}{a+b x^2} \, dx+\frac {\left (8 a^2 p^2\right ) \int \frac {x^2}{a+b x^2} \, dx}{5 b}-\frac {\left (8 a^3 p^2\right ) \int \frac {x \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\sqrt {a} \sqrt {b} \left (a+b x^2\right )} \, dx}{5 b}+\frac {1}{25} \left (8 b p^2\right ) \int \frac {x^6}{a+b x^2} \, dx \\ & = \frac {8 a^2 p^2 x}{5 b^2}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {1}{15} \left (8 a p^2\right ) \int \left (-\frac {a}{b^2}+\frac {x^2}{b}+\frac {a^2}{b^2 \left (a+b x^2\right )}\right ) \, dx-\frac {\left (8 a^3 p^2\right ) \int \frac {1}{a+b x^2} \, dx}{5 b^2}-\frac {\left (8 a^{5/2} p^2\right ) \int \frac {x \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{a+b x^2} \, dx}{5 b^{3/2}}+\frac {1}{25} \left (8 b p^2\right ) \int \left (\frac {a^2}{b^3}-\frac {a x^2}{b^2}+\frac {x^4}{b}-\frac {a^3}{b^3 \left (a+b x^2\right )}\right ) \, dx \\ & = \frac {184 a^2 p^2 x}{75 b^2}-\frac {64 a p^2 x^3}{225 b}+\frac {8 p^2 x^5}{125}-\frac {8 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{5 b^{5/2}}+\frac {4 i a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2}{5 b^{5/2}}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )+\frac {\left (8 a^2 p^2\right ) \int \frac {\tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{i-\frac {\sqrt {b} x}{\sqrt {a}}} \, dx}{5 b^2}-\frac {\left (8 a^3 p^2\right ) \int \frac {1}{a+b x^2} \, dx}{25 b^2}-\frac {\left (8 a^3 p^2\right ) \int \frac {1}{a+b x^2} \, dx}{15 b^2} \\ & = \frac {184 a^2 p^2 x}{75 b^2}-\frac {64 a p^2 x^3}{225 b}+\frac {8 p^2 x^5}{125}-\frac {184 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{75 b^{5/2}}+\frac {4 i a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2}{5 b^{5/2}}+\frac {8 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )-\frac {\left (8 a^2 p^2\right ) \int \frac {\log \left (\frac {2}{1+\frac {i \sqrt {b} x}{\sqrt {a}}}\right )}{1+\frac {b x^2}{a}} \, dx}{5 b^2} \\ & = \frac {184 a^2 p^2 x}{75 b^2}-\frac {64 a p^2 x^3}{225 b}+\frac {8 p^2 x^5}{125}-\frac {184 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{75 b^{5/2}}+\frac {4 i a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2}{5 b^{5/2}}+\frac {8 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )+\frac {\left (8 i a^{5/2} p^2\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+\frac {i \sqrt {b} x}{\sqrt {a}}}\right )}{5 b^{5/2}} \\ & = \frac {184 a^2 p^2 x}{75 b^2}-\frac {64 a p^2 x^3}{225 b}+\frac {8 p^2 x^5}{125}-\frac {184 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{75 b^{5/2}}+\frac {4 i a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2}{5 b^{5/2}}+\frac {8 a^{5/2} p^2 \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}}-\frac {4 a^2 p x \log \left (c \left (a+b x^2\right )^p\right )}{5 b^2}+\frac {4 a p x^3 \log \left (c \left (a+b x^2\right )^p\right )}{15 b}-\frac {4}{25} p x^5 \log \left (c \left (a+b x^2\right )^p\right )+\frac {4 a^{5/2} p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 b^{5/2}}+\frac {1}{5} x^5 \log ^2\left (c \left (a+b x^2\right )^p\right )+\frac {4 i a^{5/2} p^2 \text {Li}_2\left (1-\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )}{5 b^{5/2}} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 248, normalized size of antiderivative = 0.74 \[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\frac {900 i a^{5/2} p^2 \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )^2+60 a^{5/2} p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right ) \left (-46 p+30 p \log \left (\frac {2 \sqrt {a}}{\sqrt {a}+i \sqrt {b} x}\right )+15 \log \left (c \left (a+b x^2\right )^p\right )\right )+\sqrt {b} x \left (8 p^2 \left (345 a^2-40 a b x^2+9 b^2 x^4\right )-60 p \left (15 a^2-5 a b x^2+3 b^2 x^4\right ) \log \left (c \left (a+b x^2\right )^p\right )+225 b^2 x^4 \log ^2\left (c \left (a+b x^2\right )^p\right )\right )+900 i a^{5/2} p^2 \operatorname {PolyLog}\left (2,\frac {i \sqrt {a}+\sqrt {b} x}{-i \sqrt {a}+\sqrt {b} x}\right )}{1125 b^{5/2}} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.86 (sec) , antiderivative size = 612, normalized size of antiderivative = 1.82
method | result | size |
risch | \(\frac {{\ln \left (\left (b \,x^{2}+a \right )^{p}\right )}^{2} x^{5}}{5}-\frac {4 p \,x^{5} \ln \left (\left (b \,x^{2}+a \right )^{p}\right )}{25}+\frac {4 p a \,x^{3} \ln \left (\left (b \,x^{2}+a \right )^{p}\right )}{15 b}-\frac {4 p \,a^{2} x \ln \left (\left (b \,x^{2}+a \right )^{p}\right )}{5 b^{2}}-\frac {4 p^{2} a^{3} \arctan \left (\frac {b x}{\sqrt {a b}}\right ) \ln \left (b \,x^{2}+a \right )}{5 b^{2} \sqrt {a b}}+\frac {4 p \,a^{3} \arctan \left (\frac {b x}{\sqrt {a b}}\right ) \ln \left (\left (b \,x^{2}+a \right )^{p}\right )}{5 b^{2} \sqrt {a b}}+\frac {8 p^{2} x^{5}}{125}-\frac {64 a \,p^{2} x^{3}}{225 b}+\frac {184 a^{2} p^{2} x}{75 b^{2}}-\frac {184 p^{2} a^{3} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{75 b^{2} \sqrt {a b}}-\frac {4 p^{2} b \left (\munderset {\underline {\hspace {1.25 ex}}\alpha =\operatorname {RootOf}\left (b \,\textit {\_Z}^{2}+a \right )}{\sum }\left (-\frac {\left (\ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right ) \ln \left (b \,x^{2}+a \right )-2 b \left (\frac {\ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right )^{2}}{4 \underline {\hspace {1.25 ex}}\alpha b}+\frac {\underline {\hspace {1.25 ex}}\alpha \ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right ) \ln \left (\frac {x +\underline {\hspace {1.25 ex}}\alpha }{2 \underline {\hspace {1.25 ex}}\alpha }\right )}{2 a}+\frac {\underline {\hspace {1.25 ex}}\alpha \operatorname {dilog}\left (\frac {x +\underline {\hspace {1.25 ex}}\alpha }{2 \underline {\hspace {1.25 ex}}\alpha }\right )}{2 a}\right )\right ) a^{3}}{2 b^{4} \underline {\hspace {1.25 ex}}\alpha }\right )\right )}{5}+\left (i \pi \,\operatorname {csgn}\left (i \left (b \,x^{2}+a \right )^{p}\right ) {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{2}-i \pi \,\operatorname {csgn}\left (i \left (b \,x^{2}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \right )-i \pi {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{3}+i \pi {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{2} \operatorname {csgn}\left (i c \right )+2 \ln \left (c \right )\right ) \left (\frac {x^{5} \ln \left (\left (b \,x^{2}+a \right )^{p}\right )}{5}-\frac {2 p b \left (\frac {\frac {1}{5} x^{5} b^{2}-\frac {1}{3} a b \,x^{3}+a^{2} x}{b^{3}}-\frac {a^{3} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{b^{3} \sqrt {a b}}\right )}{5}\right )+\frac {{\left (i \pi \,\operatorname {csgn}\left (i \left (b \,x^{2}+a \right )^{p}\right ) {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{2}-i \pi \,\operatorname {csgn}\left (i \left (b \,x^{2}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right ) \operatorname {csgn}\left (i c \right )-i \pi {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{3}+i \pi {\operatorname {csgn}\left (i c \left (b \,x^{2}+a \right )^{p}\right )}^{2} \operatorname {csgn}\left (i c \right )+2 \ln \left (c \right )\right )}^{2} x^{5}}{20}\) | \(612\) |
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\[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\int { x^{4} \log \left ({\left (b x^{2} + a\right )}^{p} c\right )^{2} \,d x } \]
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\[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\int x^{4} \log {\left (c \left (a + b x^{2}\right )^{p} \right )}^{2}\, dx \]
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\[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\int { x^{4} \log \left ({\left (b x^{2} + a\right )}^{p} c\right )^{2} \,d x } \]
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\[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\int { x^{4} \log \left ({\left (b x^{2} + a\right )}^{p} c\right )^{2} \,d x } \]
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Timed out. \[ \int x^4 \log ^2\left (c \left (a+b x^2\right )^p\right ) \, dx=\int x^4\,{\ln \left (c\,{\left (b\,x^2+a\right )}^p\right )}^2 \,d x \]
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